Answer:
3x = [tex]e^{2}[/tex]
Step-by-step explanation:
Using the rule of logarithms
[tex]log_{b}[/tex] x = n ⇔ x = [tex]b^{n}[/tex]
Note that ln x = [tex]log_{e}[/tex] x
Given
ln(3x) = 2, then
3x = [tex]e^{2}[/tex] ← in exponential form