Answer:
[tex]A_{net} = 13.469\,m^{2}[/tex]
Explanation:
The daily energy consumption of the household is:
[tex]\Delta E_{day} = (22\,kWh)\cdot (\frac{3600000\,J}{1\,kWh} )[/tex]
[tex]\Delta E_{day} = 79200000\,J[/tex]
The needed area of solar panel to power the household is:
[tex]\Delta E_{day} = \eta\cdot G\cdot A_{net}\cdot \Delta t[/tex]
[tex]A_{net} = \frac{\Delta E_{day}}{\eta\cdot G\cdot \Delta t}[/tex]
[tex]A_{net} = \frac{79200000\,J}{(0.181)\cdot (376\,\frac{W}{m^{2}} )\cdot (86400\,s)}[/tex]
[tex]A_{net} = 13.469\,m^{2}[/tex]
