contestada

A three-point bending test is performed on a glass specimen having a rectangular cross section of height d 5 mm (0.2 in.) and width b 10 mm (0.4 in.); the distance between support points is 45 mm (1.75 in.). Compute the flexural strength if the load at fracture is 290 N (65 lb

Respuesta :

Answer:

The flexural strength of a specimen is = 78.3 M pa

Explanation:

Given data

Height = depth = 5 mm

Width = 10 mm

Length L = 45 mm

Load = 290 N

The flexural strength of a specimen is given by

[tex]\sigma = \frac{3 F L}{2 bd^{2} }[/tex]

[tex]\sigma = \frac{3(290)(45)}{2 (10)(5)^{2} }[/tex]

[tex]\sigma =[/tex] 78.3 M pa

Therefore the flexural strength of a specimen is = 78.3 M pa

Otras preguntas