A thick layer of oil is floating on the surface of water in a tank. A beam of light traveling in the oil is incident on the water interface at an angle of 33.0° from the normal. The refracted beam travels in the water at an angle of 47.5° from the normal.
What is the refractive index of the oil?

Respuesta :

Answer:

Refractive index of oil will be equal to 1.802    

Explanation:

We have given light is incident on water surface at an angle of [tex]33^{\circ}[/tex]

Let the refractive index of oil is [tex]n_1[/tex]

Light is refracted in the water at an angle of [tex]47.5^{\circ}[/tex]

Refractive index of water is [tex]n_2=1.33[/tex]

We have to find the refractive index oil

From law of refraction [tex]n_1sin\Theta_1=n_2sin\Theta _2[/tex]

[tex]n_1\times sin33^{\circ}=1.33\times sin47.5^{\circ}[/tex]

[tex]n_1\times 0.544=1.33\times 0.737[/tex]

[tex]n_1=1.802[/tex]

So refractive index will be equal to 1.802