Answer:
14°
Explanation:
From the question; we are being told that the pendulum swings through a total displacement of 28°,we are to assume that the displacement is equal on each side of the equilibrium position.
So; the amplitude of the vibration literally reflects the maximum displacement generated by a moving body, its wave is usually measured from the equilibrium position which equal to one-half of the length of the vibrating path. Having said that; the amplitude of this vibration is one-half displacement of the pendulum
i.e
A = [tex]\frac{1}{2}[/tex] of 28°
A = 14°
The amplitude of the pendulum in its equilibrium position is [tex]14^\circ[/tex].
Given that, total displacement of the pendulum is [tex]28^\circ[/tex]. Also, in the equilibrium position, the displacement is equal on each side of it.
Amplitude of the pendulum can be defined as the maximum displacement or distance moved by a point on a vibrating body in its equilibrium position.
The length of the Amplitude is usually measured as half of the length of the vibrating path in its equilibrium position.
So the Amplitude of the pendulum is,
[tex]A = \dfrac {1}{2}\times total \;displacement[/tex]
[tex]A = \dfrac {1}{2}\times 28^\circ[/tex]
[tex]A = 14^\circ[/tex]
Hence, the amplitude of the pendulum in its equilibrium position is [tex]14^\circ[/tex].
For more details, follow the link given below.
https://brainly.com/question/14840171.
