Answer:
[tex]5.36\cdot 10^{13}N[/tex]
Explanation:
The magnitude of the electricforce between two charges is given by the formula:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where:
[tex]k=8.99\cdot 10^9 Nm^{-2}C^{-2}[/tex] is the Coulomb's constant
[tex]q_1, q_2[/tex] are the two charges
r is the separation between the two charges
And the force is:
- Repulsive if the two charges have same sign
- Attractive if the two charges have opposite sign
In this problem, we have:
[tex]q_1 = 77 C[/tex] is the magnitude of the positive charge
[tex]q_2 = 77 C[/tex] is the magnitude of the negative charge
r = 1 m is the distance between the two charges
So, the magnitude of the electrostatic force is
[tex]F=(8.99\cdot 10^9)\frac{(77)(77)}{1^2}=5.36\cdot 10^{13}N[/tex]
