Respuesta :
Answer:
(a). I' = 17.24 A
(b).The current in second wire is in opposite direction compare to first wire.
Explanation:
Given data
r = 0.038 m
[tex]\frac{F}{L} =[/tex] 4.9 × [tex]10^{-5}[/tex] [tex]\frac{N}{m}[/tex]
I = 0.54 A
(a). The current in the second wire is calculated as
[tex]I'=\frac{F}{L} \frac{2 \pi r}{\mu I}[/tex]
Put all the values in above formula we get
[tex]I' =[/tex] [tex]\frac{ (2) (3.14) (0.038)}{4 \pi (0.54)} 490[/tex]
I' = 17.24 A
(b). The current in the two wires is in opposite directions because the wires repeal each other. therefore the current in second wire is in opposite direction compare to first wire.
(a)An electric current flows in a wire creates a magnetic field. The fields attract or repel depending on the direction of current flowing in it.
As given that the wires repel each other so the current in the second wire is [tex]I = 17.24 \rm A.[/tex]
(b)The wires repel each other hence the current flows in the second wire is in opposite direction.
Part (a)
Two long, parallel wires are separated by a distance of 3.80 cm.
The force per unit length that each wire exerts on the other is
The current in one wire is 0.540 A.
The formulated way to represent the current is given below.
[tex]I=\dfrac{F}{L} \dfrac{2 \pi r}{\mu I}[/tex]
Substitute the given values in the formula of current and solve it further for finding the value of I.
[tex]I = \dfrac{ (2) (3.14) (0.038) \times 4.90\times 10^{-5}}{4 \pi \times 10^{-7}(0.54)}[/tex]
[tex]I = 17.24 \rm A[/tex]
Thus, the value of the current is 17.24 Ampere.
(b) When the current flows in the same direction between wires then it generates the repulsive force and hence for the same reason, it can be concluded that the current in both the wires can be in opposite directions.
For more details, follow the link given below:
https://brainly.com/question/2625601
