Answer:
25 Nm
Explanation:
Parameters given
Distance of the particle from the origin, r = 2.0 m
Force acting on particle, F = 25 N
Angle of force, θ = 30°
The torque acting on a particle is given as:
τ = r * F * sinθ
Where r = radius of axis of rotation. This is the same as the position of the particle on the x axis.
Therefore, the torque will be:
τ = 2 * 25 * sin30
τ = 25 Nm
The torque acting on the particle is 25 Nm.
The torque about the origin of the particle is 25 Nm.
The given parameters;
The torque about the origin of the particle is calculated as follows;
[tex]\tau = Fr \times sin \ \theta \\\\\tau = 25 \times 2 \times sin(30)\\\\\tau = 25 \ Nm[/tex]
Thus, the torque about the origin of the particle is 25 Nm.
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