Answer :
The equilibrium concentration of CO is, 0.016 M
The equilibrium concentration of Cl₂ is, 0.034 M
The equilibrium concentration of COCl₂ is, 0.139 M
Explanation :
The given chemical reaction is:
[tex]CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)[/tex]
Initial conc. 0.1550 0.173 0
At eqm. (0.1550-x) (0.173-x) x
As we are given:
[tex]K_c=255[/tex]
The expression for equilibrium constant is:
[tex]K_c=\frac{[COCl_2]}{[CO][Cl_2]}[/tex]
Now put all the given values in this expression, we get:
[tex]255=\frac{(x)}{(0.1550-x)\times (0.173-x)}[/tex]
x = 0.139 and x = 0.193
We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.
Thus, we are taking value of x = 0.139
The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M
The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M
The equilibrium concentration of COCl₂ = x = 0.139 M
