Respuesta :
Answer:
The probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5
Step-by-step explanation:
We are given that . At Johnson University, the mean time is 5 hrs with a standard deviation of 1.2 hrs.
Mean = [tex]\mu = 5 hours[/tex]
Standard deviation = [tex]\sigma = 1.2 hours[/tex]
We are supposed to find the probability that the average time 100 random students on campus will spend more than 5 hours on the internet i.e. P(X>5)
[tex]Z=\frac{x-\mu}{\sigma}[/tex]
[tex]Z=\frac{5-5}{1.2}[/tex]
Z=0
P(X>5)=1-P(X<5)=1-P(Z<0)=1-0.5=0.5
Hence the probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5
