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If one had weighed out precisely 0.500 g of KIO3 for the primary standard solution and dissolved it in enough deionized water to make a 250 mL solution, the molarity of that solution would be 0.00935 M. Enter your calculated molarity of the primary standard KIO3 solution. Please use 3 significant figures.

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jamesesther1234

Answer:

Assuming the primary standard solution is made upto 1 L, its molarity would be 0.00234 mol/L to 3 s.f.

Explanation:

c1v1 = c2v2

where c1v1 and c2v2 are initial and final concentrations and volumes respectively.

c1 * 1L = 0.00935 * 0.25L

c1 = 0.002336 M

Concentration of primary solution is 0.00234 mol/L

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