What force is needed to pull one microscope slide over another at a speed of 1.00 cm/s, if there is a 0.500-mm-thick layer of 20oC water (η = 1.002 mPa∙s) between them and the contact area is 8.00 cm2?

Respuesta :

Answer:

The force required to pull one microscope is [tex]1.6 \times 10^{-5}[/tex] N

Explanation:

Given:

Area [tex]A = 8 \times 10^{-4}[/tex] [tex]m^{2}[/tex]

[tex]\eta = 1.002 \times 10^{-3}[/tex] Pa.s

Thickness [tex]dy = 0.50 \times 10^{-3}[/tex] m

Speed [tex]dv = 1 \times 10^{-2}[/tex] [tex]\frac{m}{s}[/tex]

The force needed to pull one microscope is given by,

    [tex]F = A\eta \frac{dv}{dy}[/tex]

    [tex]F = 8 \times 10^{-4} \times 1.002 \times 10^{-3} (\frac{1 \times 10^{-2} }{0.50 \times 10^{-3} } )[/tex]

    [tex]F = 1.6 \times 10^{-5}[/tex] N

Therefore, the force required to pull one microscope is [tex]1.6 \times 10^{-5}[/tex] N