Answer:
The force required to pull one microscope is [tex]1.6 \times 10^{-5}[/tex] N
Explanation:
Given:
Area [tex]A = 8 \times 10^{-4}[/tex] [tex]m^{2}[/tex]
[tex]\eta = 1.002 \times 10^{-3}[/tex] Pa.s
Thickness [tex]dy = 0.50 \times 10^{-3}[/tex] m
Speed [tex]dv = 1 \times 10^{-2}[/tex] [tex]\frac{m}{s}[/tex]
The force needed to pull one microscope is given by,
[tex]F = A\eta \frac{dv}{dy}[/tex]
[tex]F = 8 \times 10^{-4} \times 1.002 \times 10^{-3} (\frac{1 \times 10^{-2} }{0.50 \times 10^{-3} } )[/tex]
[tex]F = 1.6 \times 10^{-5}[/tex] N
Therefore, the force required to pull one microscope is [tex]1.6 \times 10^{-5}[/tex] N