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The procedure call mystery(38) will yield which output? __________ a) 0 12 b) 12 0 c) 1 1 0 2 d) 1 1 1 1 e) 2 0 1 1 public void mystery (int n) { if (n>2) mystery (n % 3); System.out.print( (n / 3) + " " ); }

Respuesta :

Answer:

Option b is the correct answer for the above question.

Explanation:

  • The mystery function is a recursive function that calls for the two times when the user passes 38 on the argument.
  • The first value is 38 and the second value is 2 for which that function is called.
  • When the value 38 is passed, then again 2 is passed because of the "mystery (n % 3);" statement.
  • This statement holds by the if condition which gives the true when the argument value is greater than 2.
  • Hence for the 2 value the if condition will not true and the function is not called again.
  • Then the 38/3 and 2/3 are printed whose value is 12 0, but it will print 0 12 because of the recursive function.
  • Hence option b is the correct answer while the other is not because other options does not states the output of this program.

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