A small commuter plane has 30 seats. The probability that any particular passenger will not show up for a flight is 0.1, independent of other passengers. The airline sells 32 tickets for the flight. What is the probability that more passengers show upthan there are seats available?

Respuesta :

Answer:

The probability will  be = 0.15641

Step-by-step explanation:

We have given-

probability that any particular passenger will not show up for a flight = 0.1

probability that any particular passenger will show up for a flight = 0.9

the prob. that more passengers show up than, this will follow binomial  distribution:

p = prob. of success = 0.9

1 - p = prob. of failure = 0.1

Pr( x = 31) + Pr(x = 32) = [tex]³²c₃₁ \times (0.9)³¹ \times (0.1)¹ + ³²c₃₂ \times (0.9)³² \times (0.1)⁰ [/tex]

                                    = 0.12208 + 0.03433

                                    = 0.15641