Respuesta :
Answer:
part(a): The potential energy is [tex]\bf{19.6~J}[/tex].
part(b): The potential energy is [tex]\bf{39.2~J}[/tex].
part(c): The potential energy is [tex]\bf{0}[/tex].
Explanation:
Given:
The mass of the ball, [tex]m = 2~Kg[/tex].
The distance from the ceiling to the center of the ball, [tex]d = 1.0~m[/tex]
The height of the room, [tex]H = 3.0~m[/tex].
The potential energy of any particle of mass [tex]m[/tex] situated at a height [tex]h[/tex] from ground is given by
[tex]V = mgh[/tex]
where [tex]g[/tex] is the acceleration due to gravity.
(a) The distance of the ball relative to ceiling is [tex]d = 1.0~m[/tex]. Thus, the potential energy will be
[tex]V &=& (2~Kg)(9.8~m/s^{2})(1.0~m)\\~~~&=& 19.6~J[/tex]
(b) The distance of the ball from the ground is [tex]h' = (3.0 - 1.0)~m = 2.0~m[/tex]
Thus, the potential energy will be
[tex]V = (2~Kg)(9.8~m/s^{2})(2.0~m)\\~~~= 39.2~J[/tex]
(c) The distance of the ball relative to a point at the same elevation as the ball is [tex]h = 0[/tex].
Thus, the potential energy will be
[tex]V = (2~Kg)(9.8~m/s^{2})(0~m)\\~~~= 0[/tex]
