A large circular loop of radius b b has a current I b Ib passing through it. The loop is held horizontally with its plane parallel to the ground. A much smaller circular loop of radius a a ( a << b a<

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Complete Question

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Answer:

The formula for mutual inductance of two concentric loops [tex]M = \frac{\pi a^2 \mu_0}{2R}[/tex]

Explanation:

Generally magnetic field in a concentric coplanar loop  is mathematically represented as

                 [tex]B = \frac{\mu_0 I_b}{2R}[/tex]

         Where [tex]\mu_o[/tex] is the permeability o free space

                     R is the radius

                    [tex]I_b[/tex] is the current

The magnetic flux  of two concentric loops is mathematically represented as

              [tex]\O = \frac{\mu_o I_b}{2R} * \pi a^2[/tex]

                 [tex]= \frac{\pi a^2 \mu_o}{2R} * I_b[/tex]

      a is the area

Generally magnetic inductance is mathematically represented as

               [tex]M = \frac{\O }{I_b}[/tex]

Substituting for  [tex]\O[/tex] in the above equation

              [tex]M = \frac{\pi a^2 \mu_0}{2R}[/tex]

               

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