Answer:
The induced current in the coil at the time 2 s is 0.00263 A
Explanation:
The equation for induced emf is equal to:
[tex]\epsilon =-\frac{d}{dt} (BAcos\theta )[/tex]
Where
B = magnetic field
A = area
θ = angle
[tex]\epsilon =-Acos0\frac{d}{dt} B\\\epsilon =-(\pi r^{2} )\frac{d}{dt} (0.5e^{-0.2t} )\\\epsilon =0.1 (\pi r^{2} )e^{-0.2t}[/tex]
For t = 2 s
[tex]\epsilon =0.1*\pi *0.05^{2} *e^{-0.2*2} =5.26x10^{-4} V[/tex]
The induced current is:
[tex]I=\frac{\epsilo }{R} =\frac{5.26x10^{-4} }{0.2} =0.00263A[/tex]
