Answer:
The entropy change of the air when the final state is 0.5 MPa and 227°C is 0.051 kJ/kg K
Explanation:
According the assumptions:
-air as ideal gas
-constant specific heats
The change of entropy is equal to:
[tex]S_{2} -S_{1} =C_{p} ln(\frac{T_{2} }{T_{1} } )-Rln(\frac{P_{2} }{P_{1} } )\\S_{2} -S_{1}=1.005ln(\frac{227+273}{27+273} )-0.287ln(\frac{0.5}{0.1} )=0.051kJ/kgK[/tex]