Answer: The partial pressure of oxygen gas in an oxygen tent is 338.85 mmHg
Explanation:
To calculate the partial pressure of oxygen gas, we use the equation given by Raoult's law, which is:
[tex]p_{O_2}=p_T\times \chi_{O_2}[/tex]
where,
[tex]p_{O_2}[/tex] = partial pressure of oxygen gas = ? mmHg
[tex]p_T[/tex] = total pressure = 753 mmHg
[tex]\chi_{O_2}[/tex] = mole fraction of oxygen gas = 0.45
Putting values in above equation, we get:
[tex]p_{O_2}=753mmHg\times 0.45\\\\p_{O_2}=338.85mmHg[/tex]
Hence, the partial pressure of oxygen gas in an oxygen tent is 338.85 mmHg