Respuesta :

Neetoo

Answer:

0.04 M

Explanation:

Given data:

Mass of Na₂SO₄= 14.2 g

Volume of solution = 2.50 L

Molarity of solution = ?

Solution:

Number of moles of Na₂SO₄:

Number of moles = mass/ molar mass

Number of moles = 14.2 g/ 142.04 g/mol

Number of moles = 0.1 mol

Molarity :

Molarity = number of moles of solute / volume of solution in L

Molarity = 0.1 mol / 2.50 L

Molarity = 0.04 M

Cricetus

The molarity of the solution will be:

"0.04 M".

Molarity of solution

According to the question,

Volume of solution = 2.50 L

Mass of Na₂SO₄ = 14.2 g

Molar mass of Na₂SO₄ = 142.04 g/mol

Now,

The number of moles will be:

= [tex]\frac{Mass}{Molar \ mass}[/tex]

By substituting the values,

= [tex]\frac{14.2}{142.04}[/tex]

= 0.1 mol

hence,

The molarity will be:

= [tex]\frac{Number \ of \ moles}{Volume \ of \ solution}[/tex]

= [tex]\frac{0.1}{2.50}[/tex]

= 0.04 M

Thus the response above is appropriate.

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