We want to solve the given quadratic equation, we will see that the solutions are: x = 2 and x = -6
So the given equation is:
[tex]x^2 + 4x - 4 = 8[/tex]
We can rewrite it as:
[tex]x^2 + 4x - 4 - 8 = 0\\\\x^2 + 4x - 12 = 0[/tex]
The solutions are given by the Bhaskara's formula, it gives:
[tex]x = \frac{-4 \pm \sqrt{4^2 - 4*1*(-12)} }{2*1} \\\\x = \frac{-4 \pm 8}{2} = -2 \pm 4[/tex]
So the two solutions are:
- x = -2 + 4 = 2
- x = -2 - 4 = -6.
If you want to learn more about quadratic equations, you can read:
https://brainly.com/question/7784687
