If 500 C of electric charge passed through a light bulb in 2 min; what is the magnitude of the average electric current passing through the bulb?

Respuesta :

Answer:

4.17 A

Explanation:

Charge is given as the product of current and time hence expressed as

Q=It

Where Q is charge in Cuolombs, I is current in Amperes and t is time in seconds

Making current, I the subject of the formula then

I=Q/t

Conversion

1 minute has 60 seconds

2 minutes will have 2*60=120 seconds

Substituting 120 s for t and 500 C for Q then

I=500÷120=4.1666666666666666666666666666666666666666

Rounded off, current is approximately 4.17A