researchdevelopmento
contestada

PLEASE answer! BIIIGGG POINTS! Will award brainliest!!!
It takes 125.0 mL of 3.5 M hydrobromic acid to neutralize 75.0 mL of lithium hydroxide. What is the concentration of lithium hydroxide? ____/10 points HBr (aq) + LiOH (aq) → H2O (l) + LiBr (aq)

Respuesta :

Neetoo

Answer:

5.83 M

Explanation:

Given data:

Volume of HBr = 125.0 mL

Molarity of HBr solution = 3.5 M

Volume of LiOH = 75.0 mL

Molarity of LiOH = ?

Solution:

Formula:

M₁V₁  = M₂V₂

M₁ = Molarity of HBr

V₁  = Volume of HBr

M₂ = Molarity of LiOH

V₂ = Volume of LiOH

Now we will put the values.

3.5 M  ×125.0 mL  =  M₂ × 75.0 mL

437.5 M.mL = M₂ × 75.0 mL

M₂ = 437.5 M.mL / 75.0 mL

M₂ = 5.83 M

laik02076

Answer:

[tex]5.83 M[/tex]

Explanation:

[tex]M_{2}= \frac{(3.5M)(125mL)}{75mL} =5.83M[/tex]

This is just a different way of writing the equation the other answer did a very good job of explaining, there isn't much I can add, but I hope this helps someone!   :)

Otras preguntas