In a certain Algebra 2 class of 28 students, 23 of them play basketball and 12 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

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Answer:

10/28

Step-by-step explanation:

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Probability that a student chosen randomly plays both basketball and baseball is 0.586.

What is Probability?

"Probability is simply how likely something is to happen. Whenever we're unsure about the outcome of an event, we can talk about the probabilities of certain outcomes—how likely they are."

Number of Students = 28

Number of students neither playing both games = 3

Number of students playing = 29-3 = 26

Number of students playing both games = 23+12-26 = 9

Number of students playing only basketball = 23-9 = 14

Number of students playing only baseball = 12-9 = 3

Number of students playing  both basketball and baseball = 14+3 = 17

Probability that a student chosen randomly from a class plays basketball and baseball:

P = [tex]\frac{17}{29}[/tex] = 0.586

Hence, Probability that a student chosen randomly from a class plays basketball and baseball is 0.586.

Learn more about probability here

https://brainly.com/question/11234923

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