yashiyahgaston
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a family ordered some candy bars and bags of chips for snacking the number of candy bars was twice as much as the number of bags of chips if the family spent a total of 5.50 how many bags of chips did the family buy if each candy bar is $1.00 and each bag of chips is $0.75

Respuesta :

173darkknight

Answer:

The family bought 2 bags of chips.

Step-by-step explanation:

Let chips = C

Let candy bars = B

C + 2B = 5.50

(0.75) + 2(1.00) = 5.50

The right side (5.50) is held constant.

What must the left side [(0.75) +2(1.00)] be multiplied by to equal 5.50?

Left side = 0.75 + 2(1.00)= 2.75

5.50/ 2.75 = 2

Multiply left side by 2 to equal 5.50

2 × (0.75 + 2 × 1.00) = 5.50

1.50 + 4 = 5.50

Or :

2 × (C + 2B) = 5.50

2 Bags of chips were bought.

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