The equilibrium constant of the reaction is 1.45 × 10^12.
The reaction equation as written is;
2Ce4+(aq) + 2Cl−(aq) ⇌ 2Ce3+(aq) + Cl2(g)
Now, we can recall the formula;
E°cell = 0.0592/n log K
n = Number of electrons transferred
E°cell = E°cathode - E°anode
E°cathode = 1.72 V
E°anode = 1.36 V
E°cell = 1.72 V - 1.36 V = 0.36 V
Note that two electrons were transferred, hence;
0.36 = 0.0592/2 log K
0.36 = 0.0296 log K
log K = 0.36/0.0296
K = Antilog(0.36/0.0296)
K = 1.45 × 10^12
Learn more: https://brainly.com/question/24381583
