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In 2000, NASA placed a satellite in orbit around an asteroid. Consider a spherical asteroid with a mass of 1.50×1016 kg and a radius of 9.00 km .What is the speed of a satellite orbiting 4.60 km above the surface?

Respuesta :

Answer:

8.58 m/s.

Explanation:

Given,

Mass of the asteroid,M = 1.50 x 10¹⁶ Kg

radius = 9 Km

distance of the satellite, r = 4.60 Km

Speed of the satellite  = ?

R = 9 + 4.60 = 13.60 Km

Speed of the satellite rotating in orbit

[tex]v = \sqrt{\dfrac{GM}{R}}[/tex]

G is gravitational constant

[tex]v = \sqrt{\dfrac{6.67\times 10^{-11}\times 1.50\times 10^{16}}{13.60\times 10^3}}[/tex]

v = 8.58 m/s

Speed of the satellite is equal to 8.58 m/s.

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