Answer with Explanation:
We are given that
One food calorie=4KJ=[tex]4\times 1000=4000J[/tex]
1kJ=1000 J
Height,h=3 m
Mass,m=2500 kg
Energy required to lift the truck=[tex]mgh[/tex]
Where [tex]g=9.8m/s^2[/tex]
Using the formula
Energy required to lift the truck=[tex]2500\times 3\times 9.8[/tex]
Energy required to lift the truck=73500J=[tex]\frac{73500}{1000}=7.35KJ[/tex]
If a food item gives 20 food calorie
Then, the energy obtained from food=[tex]20\times 4=80KJ[/tex]
Which is greater than the energy required to lift the truck.