Respuesta :
Answer: [tex]Rate=k[L]^1[M]^2[/tex]
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
[tex]L+M\rightarrow products[/tex]
[tex]Rate=k[L]^x[M]^y[/tex] (1)
k= rate constant
x = order with respect to L
y = order with respect to M
n =( x+y)= Total order
a) If [L] is doubled, the reaction rate will increase by a factor of 2:
[tex]2\times Rate=k[2L]^x[M]^y[/tex] (2)
b) If [M] is doubled, the reaction rate will increase by a factor of 4:
[tex]4\times Rate=k[L]^x[2M]^y[/tex] (3)
Dividing 2 by 1:
[tex]\frac{2\times Rate}{Rate}=\frac{k[2L]^x[M]^y}{k[L]^x[M]^y}[/tex]
[tex]2=2^x[/tex]
[tex]x=1[/tex]
Dividing 3 by 1
[tex]\frac{4\times Rate}{Rate}=\frac{k[L]^x[2M]^y}{k[L]^x[M]^y}[/tex]
[tex]4=2^y[/tex]
[tex]2^2=2^y[/tex]
[tex]y=2[/tex]
Thus rate law is: [tex]k[L]^1[M]^2[/tex]
