Lifetime of electronics: In a simple random sample of 100 electronic components produced by a certain method, the mean lifetime was 125 hours. Assume that component lifetimes are normally distributed with population standard deviation σ = 20 hours.

Construct a 99.5% confidence interval for the mean battery life. Round the answer to the nearest whole number.

Respuesta :

Answer:

The 99.5% confidence interval for the mean battery life is between 119 and 131 hours.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.9995}{2} = 0.0025[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.0025 = 0.9975[/tex], so [tex]z = 2.81[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

[tex]M = 2.81*\frac{20}{\sqrt{100}} = 6[/tex]

The lower end of the interval is the sample mean subtracted by M. So it is 125 - 6 = 119 hours

The upper end of the interval is the sample mean added to M. So it is 125 + 6 = 131 hours.

The 99.5% confidence interval for the mean battery life is between 119 and 131 hours.