Answer:
Explanation:
Given that,
Capacitance of the capacitor is
C = 0.350 µF = 0.35 × 10^-6 F
Time constant ranges from
τ(min) = 2.5s
τ(max) = 17s
We want to find the range the resistance
Now, using the time constant formulae
τ = RC
Then, R= τ/C
So,
R(min) = τ(min) /C
R(min) = 2.5 / 0.35 × 10^-6
R(min) = 7.143 × 10^6 Ω
R(min) = 7.143 MΩ
R(max) = τ(max) /C
R(max) = 17 / 0.35 × 10^-6
R(max) = 48.57 × 10^6 Ω
R(max) = 48.57 MΩ
So the resistance ranges from
7.143 MΩ < R < 48.57 MΩ