Respuesta :
Answer: Molarity of [tex]Cl^-[/tex] anions in the chemist's solution is 0.0104 M
Explanation:
Molarity : It is defined as the number of moles of solute present per liter of the solution.
Formula used :
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute
[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.049g}{95g/mol}=5.2\times 10^{-4}moles[/tex]
[tex]V_s[/tex] = volume of solution in ml = 100 ml
Now put all the given values in the formula of molarity, we get
[tex]Molarity=\frac{5.2\times 10^{-4}moles\times 1000}{100ml}=5.2\times 10^{-3}mole/L[/tex]
Therefore, the molarity of solution will be [tex]5.2\times 10^{-3}mole/L[/tex]
[tex]MgCl_2\rightarrow Mg^{2+}+2Cl^-[/tex]
As 1 mole of [tex]MgCl_2[/tex] gives 2 moles of [tex]Cl^-[/tex]
Thus [tex]5.2\times 10^{-3}[/tex] moles of [tex]MgCl_2[/tex] gives =[tex]\frac{2}{1}\times 5.2\times 10^{-3}=0.0104[/tex]
Thus the molarity of [tex]Cl^-[/tex] anions in the chemist's solution is 0.0104 M
