Answer : The heat energy required to melt 2 kg of ice was, 667.7 kJ
Explanation :
First we have to calculate the moles of ice.
[tex]\text{Moles of ice}=\frac{\text{Given mass ice}}{\text{Molar mass ice}}=\frac{2kg}{18g/mol}=\frac{2000g}{18g/mol}=111.1mol[/tex]
Now we have to calculate the heat energy.
As, heat energy required to melt 1 mole of ice = 6.01 kJ
So, heat energy required to melt 111.1 mole of ice = 111.1 × 6.01 kJ
= 667.7 kJ
Therefore, the heat energy required to melt 2 kg of ice was, 667.7 kJ
