PLEASE HELP!! S is the center of the circle. Suppose that JK=12, LK=12, NS=8, and PS= 2x - 6. Fine the following

Answer:
x = 7
LP = 6
Step-by-step explanation:
JK = 12
LK = 12
NS = 8
PS = 2x - 6
radius bisects the chords JK and LK because it is perpendicular to them.
JK = JN + NK = 6 + 6 = 12
LK = LP + PK = 6 + 6 = 12
LP = 6
radius= root(6^2 + 8^2) = 10 then PS = 8 = 2x -6,
8 = 2x - 6
14 = 2x
x = 7