Answer:
Explanation:
Mirror formation in mirror A
focal length f = - 10 cm ( concave mirror )
Let u be object distance , v is image distance .
In case image is virtual
v / u = 2
v = 2u
Mirror formula
[tex]\frac{1}{v} +\frac{1}{u} =\frac{1}{f}[/tex]
Putting the values
[tex]-\frac{1}{2u} +\frac{1}{u} =-\frac{1}{10}[/tex]
[tex]\frac{1}{2u}[/tex] = [tex]-\frac{1}{10}[/tex]
u = -5 cm
In case image is real
[tex]\frac{1}{v} +\frac{1}{u} =\frac{1}{f}[/tex]
[tex]\frac{1}{2u} +\frac{1}{u} =-\frac{1}{10}[/tex]
[tex]\frac{3}{2u} =-\frac{1}{10}[/tex]
u = [tex]-\frac{30}{2}[/tex]
u = - 15 cm
