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When playing American​ roulette, the croupier​ (attendant) spins a marble that lands in one of the 38 slots in a revolving turntable. The slots are numbered 1 to​ 36, with two additional slots labeled 0 and 00 that are painted green. Consider the numbers 0 and 00 as neither even nor odd. Half the remaining slots are colored red and half are black. Assume a single spin of the roulette wheel is made. Find the probability of the marble landing on a 00 or even slot. The total number of outcomes is and the number of outcomes in the event is

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Answer:

Check the explanation

Step-by-step explanation:

1) probability for odd or 00 = (18+1)/38 = 0.5

2) expected value can be calculated as follows :

14 * win probability - 13 * lose probability

=14 * (18/38) - 13*(20/38)

= -0.21

Using it's concept, it is found that there is a 0.5 = 50% probability of the marble landing on a 00 or even slot.

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem:

  • There are 38 slots, hence [tex]T = 38[/tex].
  • Of those, 18 are even, plus 00, hence [tex]D = 19[/tex]

The desired probability is:

[tex]p = \frac{D}{T} = \frac{19}{38} = 0.5[/tex]

0.5 = 50% probability of the marble landing on a 00 or even slot.

A similar problem is given at https://brainly.com/question/15536019

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