Answer:
{120°, 420°, 480°, 780°, 840°}
Step-by-step explanation:
From your knowledge of the short table of trig functions, you know that ...
sin(60°) = (√3)/2
and that the sine of the supplement of this angle has the same value. Of course, the sine function is periodic with period 360°, so the solutions will all be of the form ...
θ = 90° ± 30° + k·360°
for any integer k.
For the range of interest, the angles are ...
90° +30° = 120°
360° +90° -30° = 420°
360° +90° +30° = 480°
2·360° +90° -30° = 780°
2·360° +90° +30° = 840°
