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Stoichiometry Assessment A
1. If 13.5 moles of oxygen are reacted with an excess of ammonia, how many moles of NO and of H20 are
formed given the following reaction? Show all work for credit.
4 NH3 + 502 ---> 4 NO + 6H20

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mahesh11

Answer:

NO=10.8Mol

H2O=16.2Mol

Explanation:

4NH3 + 5O2 --> 4NO + 6H2O

5Mol of O2 Produce 4Mol of NO

Therefore 13.5Mol of O2 produce NO = (13.5/5)x4 = 10.8

H2O Mol = (13.5/5) x 6 = 16.2

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