Answer:
[tex]\dfrac{-e^6}{5}[/tex]
Step-by-step explanation:
Maybe you want to simplify ...
[tex]\dfrac{-2e^8-8e^7}{10e^2+40e}=\dfrac{-2e^7(e+4)}{10e(e+4)}=\boxed{\dfrac{-e^6}{5}}[/tex]
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The distributive property and the rules of exponents are useful.
ab +ac = a(b+c)
(a^b)(a^c) = a^(b+c)
1/a^b = a^-b
