Respuesta :
Explanation:
ESTE PROBLEMA ES MEJOR HACERLO EN SI. PRIMERO CONVIERTES
LA VELOCIDAD INICIAL Y LA VELOCIDAD FINAL A m/s
[tex]v_{0}[/tex] = 33.52 m/s v = 53.67 m/s x = 3220 m
PRIMERO ENCUENTRAS LA ACELERACIÓN DEL COCHE CON LA ECUACIÓN
DE GALILEO GALILEI
a = [tex](53.67 m/s)^{2} - (33.52 m/s)^{2}/3220 m[/tex] = [tex]0.5453 m/s^{2}[/tex]
AHORA CON LA ACELERACIÓN USMOS LA SEGUNDA LEY DE NEWTON
F = 75 kg([tex]0.5453 m/s^{2}[/tex]) = 40.9 N
the force exerted by the mass is 204 N.
The given parameters;
mass of the car, m 750 kg
initial speed of the car, u = 75 mph
final speed of the car, v = 120 mph
distance traveled by the car, s = 2 miles
The acceleration of the car is calculated as;
[tex]v^2 = u^2 + 2as\\\\2as = v^2 - u^2\\\\a = \frac{v^2 - u^2}{2s} \\\\a = \frac{120^2 - 75^2}{2\times 2} \\\\a = 2193.75 \ mi/hr^2\\\\a = 2193.75 \frac{mi}{hr^2} \times \frac{1609.3 \ m}{1 \ mile} \times \frac{1hr^2}{(3600 \ s)^2} \\\\a = 0.272 \ m/s^2[/tex]
The force exerted by the mass is calculated as follows;
F = ma
F = 750 x 0.272
F = 204 N
Thus, the force exerted by the mass is 204 N.
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