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In an isosceles triangle, the equal sides are 2/3 if the length of the base. Determine the measure if the base angles.
Please help me with good explanation, I have a trig exam soon!

Respuesta :

znk

Answer:

41.41°  

Step-by-step explanation:

In ∆ABC below, the legs are 4 and the base is 6.

So, the legs are ⅔ the length of the base.

In ∆CBD,

cosB = BD/BC = 3/4 = 0.75

B = arccos 0.75 = 41.41°

The base angles are each 41.41°

Ver imagen znk

The measure should be 41.41°  

Calculation of the measure:

Since In ∆ABC , the legs should be 4 and the base should be 6.

Now

the legs are two-third the length of the base.

Also,

In ∆CBD,

cosB [tex]= BD\div BC = 3\div 4 = 0.75[/tex]

So,

B = arccos 0.75 = 41.41°

Therefore, we can concluded that The base angles are each 41.41°

Learn more about length here: https://brainly.com/question/3385843

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