Respuesta :
Answer:
(a) 2ab - a/b
(b) c² + d + 2cd
(c) c + c²
(d) Let x be the number that is 1 greater than b, then x = b + 1
Let y be the number twice as large as b, then y = 2b
Then the quotient of x and y is what we want. This is (b + 1)/2b
(e) pq - 3(p + q)
(f) The quotient of n² and n³ + 5, this is
n²/(n³ + 5)
Answer:
a) 2*a*b - a/b
b) c² + d + 2*c*d
c) c + c²
d) (1 + b)/(2*b)
e) p*q - 3*(p+q)
f) n²/(n+5)³
Step-by-step explanation:
We can divide each statement into its parts, as follows:
a) The difference between:
- twice the product of a and b: 2*a*b
- and the quotient of these numbers: a/b
b) The sum of:
- square of c: c²
- and d increased by twice their product. d+2*c*d
c) The sum of:
- a number c: c
- and its square: c²
d) The quotient of:
- the number that is 1 greater than a number b: 1 + b
- and the number that is twice as large as b: 2*b
e)
- The product of two numbers, p and q: p*q
- decreased by three times their sum: 3*(p+q)
f) The quotient of:
- the square of a number n: n²
- and the cube of n increased by 5: (n+5)³
