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Rectangle ABCD has vertices A(–6, –2), B(–3, –2), C(–3. –6), and D(–6, –6). The rectangle is translated so that the coordinates of the image are A’(–10, 1), B’(–7,1), C’(–7, –3), and D’(–10, –3). Which rule was used to translate the image

Respuesta :

MasterElodin
We are given:

Rectangle ABCD with the following vertices:
A (-6, -2)
B (-3, -2)
C (-3, -6)
D (-6, -6)

The rectangle was translated so it would result to the following coordinates:

A' (-10, 1)
B' (-7, 1)
C' (-7, -3)
D' (-10, -3)

Now, to figure out how the rectangle was translated, consider vertex A:

A (-6, -2) and translated vertex A' (-10, 1)

subtract the x and y coordinates:

x: -10 - (-6) = (-) 4 ; this means that the vertex is translated 4 units to the left.
y: 1 - (-2) = (+) 4; this means that the vertex is translated 4 units up.
Riia

It is given in the question that Rectangle ABCD has vertices A(–6, –2), B(–3, –2), C(–3. –6), and D(–6, –6). The rectangle is translated so that the coordinates of the image are A’(–10, 1), B’(–7,1), C’(–7, –3), and D’(–10, –3).

Let's take  A and A'. In A', the  x coordinate moves left by 4 units and the y coordinates ,moves up by 3 units .

So the rules is

(x,y)->(x-4,y+3)


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