Answer:
[tex]\fbox{\begin{minipage}{5em}13. 0.830\\14. 0.800\\15. 0.391\\16. 0.750\end{minipage}}[/tex]
Step-by-step explanation:
A right triangle with 3 sides: adjacent side, opposite side and hypotenuse (as shown in attached picture)
According to the trigonometric properties:
[tex]sin(theta) = \frac{opposite}{hypotenuse}[/tex]
[tex]cos(theta) = \frac{adjacent}{hypotenuse}[/tex]
[tex]tan(theta) = \frac{opposite}{adjacent}[/tex]
[tex](adjacent)^{2} + (opposite)^{2} = (hypotenuse)^{2}[/tex]
[tex](adjacent)^{2} = (hypotenuse)^{2} - (opposite)^{2}[/tex]
[tex](opposite)^{2} = (hypotenuse)^{2} - (adjacent)^{2}[/tex]
Use the above formulas with corresponding sides:
[tex]13) cos(theta) = \frac{9}{3\sqrt{13} } = 0.83[/tex]
[tex]14) sin(theta) = \frac{\sqrt{5^{2}-3^{2} } }{5} = \frac{4}{5} = 0.8[/tex]
[tex]15) sin(theta) = \frac{9}{\sqrt{(8\sqrt{7}) ^{2} + 9^{2} } } = 0.391[/tex]
[tex]16) tan(theta) = \frac{3}{4} = 0.75[/tex]
Hope this helps!
:)
