Could someone help me with this trigonometry question.

Answer:
About 75 degrees
Step-by-step explanation:
Let's call the point between C and B D. Using the Pythagorean Theorem, you know that CD is [tex]\sqrt{112}[/tex]cm, meaning that BC has length [tex]8+\sqrt{112}[/tex]cm. Additionally, we know that AB has length [tex]\sqrt{208}[/tex]. Using the law of cosines:
[tex](8+\sqrt{112})^2=16^2+208-2(16)(\sqrt{208})\cdot \cos(A) \\\\345.328=256+208-461.511\cos(A) \\\\-461.511\cos(A)=-118.672 \\\\A=\cos^{-1}(0.2571)\approx 75^{\circ}[/tex]
Hope this helps!