contestada

The figure below shows line t, which intersects segment AB:
In the image above, line t is a perpendicular bisector and angle 4 is congruent to angle 6. Write a paragraph to prove that point C is equidistant from points A and B.

The figure below shows line t which intersects segment AB In the image above line t is a perpendicular bisector and angle 4 is congruent to angle 6 Write a para class=

Respuesta :

Answer:

Below.

Step-by-step explanation:

So first draw lines CA and CB.

So t is a perpendicular bisector so AOC and BOC are 90°. (O is the center).

You can then use the reflexive property and say OC = OC.

Since t is an perpendicular bisector, AO = BO.

Now, you can say triangle AOC is congruent to triangle BOC by SAS, or LL.

AC = BC by CPCTC.

C is equidistant because that is the definition.

olayemiolakunle65

A perpendicular bisector to a given line is a line that divides the given line into two equal parts, and which is at right angle to the given line. The required paragraph is: since tC is the perpendicular bisector of AB, any point on the line segment (tC) would be equidistant form points A and B.

A perpendicular bisector is a constructed line at right angle, which divides a given line into two equal parts at right angle.

The required explanation to the diagram so as to arrive at the final conclusion are:

tC is the perpendicular bisector of AB (given)

< 4 ≅ < 6 = [tex]90^{o}[/tex] (right angle property)

segment A4 ≅ B6 (property of a bisected segment)

segment t4 ≅ t6 (perpendicular bisector)

⇒ C4 ≅ C6 (common segment property)

Therefore, since tC is the perpendicular bisector of AB, any point on the line segment (tC) would be equidistant from points A and B.

Visit: https://brainly.com/question/929137

Otras preguntas