Respuesta :
Let's work out the process to find the numerator:
(x+2)/2 - (x+1)/3x Factor using the LCD, 6x
3x(x+2)/6x - 2(x+1)/6x
(3x² + 6x - 2x - 2)/6x
= (3x² + 4x - 2)/6x
Answer is B) 3x² + 4x - 2
(x+2)/2 - (x+1)/3x Factor using the LCD, 6x
3x(x+2)/6x - 2(x+1)/6x
(3x² + 6x - 2x - 2)/6x
= (3x² + 4x - 2)/6x
Answer is B) 3x² + 4x - 2
Answer: (B) 3x² + 4x - 2 will be numerator of the required fraction.
Explanation: According to the question,
Given expression: (x+2)/2 - (x+1)/3x ----------(1)
Since, the least common factor of 2 and 3x= 6x
So, from equation (1), 3x(x+2)/6x - 2(x+1)/6x
=(3x² + 6x - 2x - 2)/6x
= (3x² + 4x - 2)/6x, here, 3x² + 4x - 2 is numerator and 6x is denominator.
Thus, required answer is 3x² + 4x - 2.