Answer:
Option C.
Step-by-step explanation:
Note: It is given question and option "=" sing is missing. On some places it should be "=" instead of "=".
Consider the given equation is
[tex]\log_2(x+11)=4[/tex]
Using properties of \logarithm we get
[tex](x+11)=2^4[/tex] [tex][\because \log_ax=b\Leftightarrow x=a^b][/tex]
[tex]x+11=16[/tex]
[tex]x=16-11[/tex]
[tex]x=5[/tex]
The solution is x=5.
To check the solution, substitute x=5 in the given equation.
[tex]\log_2(5+11)=4[/tex]
[tex]\log_2(16)=4[/tex]
[tex]\log_22^4=4[/tex]
[tex]4=4[/tex]
[tex]LHS=RHS[/tex]
Therefore, x-5 is a true solution because [tex]\log_2(16)=4[/tex].
Answer:
C x = 5 is a true solution because log Subscript 2 Baseline (16) = 4
Step-by-step explanation:
