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Assign oxidation numbers in the following corrosion reactions for copper. Tell which substances are oxidized and which are reduced. 2Cu (s) + 1⁄2 O2 (g) → Cu2O (s) Cu2O (s) + 1⁄2 O2 (g) → 2CuO (s)

Respuesta :

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2 Cu + 1/2 O2 --> Cu2O + Cu2O + 1/2 O2 --> 2CUO

Copper is oxidized since it went from being an oxidation number of 0 to +2.

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