Hey there!
Your question states: You dissolve 0.005 mol of potassium chloride (KCI) in0.50 L of water. What is the molarity of the solution? So, basically in this question here, this would be just like converting the cup's to gallons. It would be the exact same thing.
The, when doing this problem, we would do the following . . .
[tex] \left \{\boxed{\boxed{0.005}} \ divided \ by \ \boxed{\boxed{0.50}} \ { \atop {}} \right.\}[/tex]
[tex]and \ from \ doing \ this, \ we \ get \ for \ your \ and . . . [/tex]
[tex]\boxed{\boxed{ .01m}}[/tex]
Hope this helps.
~Jurgen
